Police Car
A speeding motorist passes a stopped police car. How fast is the speeding car going?
I need this explained to me, not just answered.
A speeding motorist passes a stopped police car. At the moment the car passes, the police car starts from rest with a constant acceleration of 4.28 m/s2. The speeding motorist continues with constant velocity until caught by the police car14.8s later. How fast is the speeding car going?
Thank you, Druisse! My main problem is really just.. understanding the problem! Ha ha! Your help is greatly appreciated. To the two who said he wasn’t fast enough.. thank you, too! I thought it funny. (=
The answer is apparently 31.7 m/s. Why should it be divided by 2?
When the police car catches the speeding car they certainly do not have the same velocity. The police car catches up with the speeding car because it has a higher velocity than the speeding car. What is true is : They have covered the same distance, and/ or been travelling for the same time.
What distance did the police go travel?
s = ut + 0.5*a*t²
s = 0 + 0.5*4.28*14.8²
s = 468.75m
The speeding car traveled 468.75m in 14.8 sec,
Velocity of car = 468.75/14.8 = 31.68 m/s
Answer: 31.7m/s
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